KVPY Sample Paper KVPY Stream-SX Model Paper-30

  • question_answer
    The 288th term of the series a, b, b, c, c, c, d, d, d, d, e, e, e, e, e, f, f, f, t, f, f,.............. is

    A) u

    B) v              

    C) w

    D) x

    Correct Answer: D

    Solution :

    a, bb, c,c,c, d,d,d,d, ?. Consider the arrangement of n letters.
    Then, \[1+2+3+...+n=\frac{n(n+1)}{2}\le 288\]
    i.e., \[{{n}^{2}}+n-576\le 0\]    \[\therefore \,\,\,\,\,\,\,\,\,n\le 23\]
    \[\therefore \]if we write up to 23 letters i.e., upto w, the total number of terms
    \[=1+2+3+...+23=\frac{23\times 24}{2}=276\]
    \[\therefore \]terms from 276 to 300 are the letter x each
    \[\therefore \]      288th letter is x.


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