A) There would be equal chances for both having free or attached earlobes and sparse hair on pinnae.
B) They would have hairy pinnae and there would be 1 in 8 chance that both will have attached earlobes.
C) There is an equal chance for the two to have either hairy pinnae or sparse hair on pinnae.
D) Both will have free earlobes and extensive hair on pinnae.
Correct Answer: A
Solution :
| Genotype for attached earlobe =` Aa or AA Genotype of free earlobe = aa |
| Because son with free earlobes is born, male parent with attached earlobe and hairy pinna will be heterozygous for earlobe trait, that is, Aa (XY). Genotype of his daughter with attached earlobe-Aa (XX) |
| Genotype of male with free earlobes and sparse hair on pinna = aa where \[{{\operatorname{Y}}^{\operatorname{s}}}\] designate pinna with sparse hair. |
| Parents: Aa (XX) \[\times \] aa \[\left( X{{Y}^{s}} \right)\] |
| Offspring: Aa (XX), Aa (XY8). Aa (XX), aa \[\left( X{{Y}^{s}} \right)\] |
| Since only two sons are born to them, both have equal chances of getting free or attached earlobes. |
You need to login to perform this action.
You will be redirected in
3 sec
