question_answer

In the circuit shown in figure potential difference between A and B is:

A) 30 V    

B) 60 V

C) 10 V

D) 90 V

Correct Answer: C

Solution :

\[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{\left( \frac{15}{4} \right)C}{C}=\frac{15}{4};\,\,\,\therefore \,\,\,\,\,\,{{V}_{2}}=\left( \frac{4}{19} \right)(190)=40V\]

Now this 40V is distributed in C and 3C in the

ratio of \[\frac{3}{1}\]

\[\therefore \,\,\,\,\,\,{{V}_{AB}}=10V\]