KVPY Sample Paper KVPY Stream-SX Model Paper-31

2 mole, equimolar mixture of \[N{{a}_{2}}{{C}_{2}}{{O}_{4}}\] and \[{{H}_{2}}{{C}_{2}}{{O}_{4}}\] required \[{{V}_{1}}L\] of 0.1 M \[KMn{{O}_{4}}\] in acidic medium for complete oxidation. The same amount of the mixture required \[{{V}_{2}}L\] of 0.2 M \[NaOH\]for neutralization. The ratio of Vi to Vi is -

A) 1 : 2

B) 2 : 1

C) 4 : 5

D) 5 : 4

Correct Answer: C

Solution :

eQ. of \[N{{a}_{2}}{{C}_{2}}{{O}_{4}}\] + eQ. of \[{{H}_{2}}{{C}_{2}}{{O}_{4}}\] = eQ. of \[KMn{{O}_{4}}=V\,\,\times \,\,0.1\,\,\times \,\,5\]

\[2+2=0.5V;\,\] \[V=8L\]

eQ. of \[{{H}_{2}}{{C}_{2}}{{O}_{4}}=eQ.\]of \[NaOH\] \[\Rightarrow \,\,\,1\,\,\times \,\,2=0.2\,\,\times \,\,{{V}_{2}};{{V}_{2}}=10L\]

Hence, \[{{V}_{1}}:{{V}_{2}}=8:10=4:5\]