A) \[2.303\,\,M\,\,{{\min }^{-1}}\]
B) \[0.2303\,\,M\,\,{{\min }^{-1}}\]
C) \[0.1\,\,M\,\,{{\min }^{-1}}\]
D) None of these
Correct Answer: B
Solution :
| \[k=\frac{2.303}{t}\log \,\,\left( \frac{{{C}_{{{A}_{0}}}}}{{{C}_{A}}} \right)\] |
| \[2.303\,\,\times \,\,1=2.303\,\,\log \left( \frac{{{C}_{{{A}_{0}}}}}{{{C}_{A}}} \right)\] |
| \[\frac{{{C}_{{{A}_{0}}}}}{{{C}_{A}}}=10\] |
| \[\therefore \,{{C}_{A}}\Rightarrow \frac{1}{10}\Rightarrow 0.1\] |
| Rate after 1 min \[{{r}_{1}}=k.{{C}_{A}}\] \[\Rightarrow 2.303\times 0.1\] \[\Rightarrow 0.2303\,\,M\,{{\min }^{-1}}\] |
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