| Consider the following changes: | |
| \[M(s)\to M(g)\] | ... (1) |
| \[M(s)\to {{M}^{2+}}(g)+2{{e}^{-}}\] | ... (2) |
| \[M(g)\to {{M}^{+}}(g)+{{e}^{-}}\] | ... (3) |
| \[{{M}^{+}}(g)\to {{M}^{2+}}(g)+{{e}^{-}}\] | ... (4) |
| \[M(g)\to {{M}^{2+}}(g)+2{{e}^{-}}\] | ... (5) |
| The second ionization energy of M could be calculated from the energy values associated with | |
A) \[1+3+4\]
B) \[2-1+8\]
C) \[1+5\]
D) \[5-3\]
Correct Answer: D
Solution :
Second ionization energy is amount of energy required to take out an electron from the monopositive cation. Hence, \[M(g)\to {{M}^{2+}}+2{{e}^{-}}\] \[M(g)\to {{M}^{+}}+{{e}^{-}}\]
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