A) increasing in (0, 1) and decreasing (1,2)
B) decreasing in (0, 1) and increasing (1,2)
C) increasing in (0, 2)
D) decreasing in (0, 2)
Correct Answer: B
Solution :
\[f''(x)>0,y=f(x);x\in (0,2)\] |
\[\phi (x)=f(x)+f(2-x)\] |
\[\phi '(x)=f'(x)-f'(2-x)\] |
for\[\phi (x)\]to be increasing |
\[\phi '(x)>0\]\[\Rightarrow \]\[f'(x)>f'(2-x)\]\[\Rightarrow \]\[x>2-x\] |
\[(f'(x)\]is increasing in (0, 2)\[\Rightarrow \]\[x>1\]\[\Rightarrow \]\[x\in (1,2)\] |
For\[\phi '(x)\]to be decreasing |
\[\phi '(x)<0\]\[\Rightarrow \]\[f'(x)<f'(2-x)\] |
\[\therefore \] \[x\in (0,1).\] |
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