A) \[{{[Zn{{(N{{H}_{3}})}_{6}}]}^{2+}}\]
B) \[{{[\,Ni\,{{(N{{H}_{3}})}_{6}}]}^{2+}}\]
C) \[{{[Cr{{(N{{H}_{3}})}_{6}}]}^{3+}}\]
D) \[{{[Co\,{{(N{{H}_{3}})}_{6}}]}^{3+}}\]
Correct Answer: D
Solution :
[D]| [a] Because of \[3{{d}^{10}}\] configuration no \[\left( n-1 \right)d\] orbital is available for \[{{d}^{2}}s{{p}^{3}}\] hybridization and thus forms outer orbital complex. The complex is diamagnetic. |
| [b] Because of \[3{{d}^{8}}\]configuration no \[\left( n-1 \right)d\] orbital is available for \[{{d}^{2}}s{{p}^{3}}\] hybridization and thus forms outer orbital complex. The complex is paramagnetic with two unpaired electrons. |
| [c] The complex is inner orbital complex but \[3{{d}^{3}}\] configuration has three unpaired electrons with weak as well as with strong field ligand. |
| [d] In the diamagnetic octahedral complex,\[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}},\]the cobalt ion is in +3 oxidation state. |
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