KVPY Sample Paper KVPY Stream-SX Model Paper-3

  • question_answer
    Consider the following reactions at 300 K.
    A\[\to \]B (uncatalysed reaction)
    A\[\xrightarrow{catalyst}\]B (catalyst reaction)
    The activation energy is lowered by \[8.314\text{ }kJ\text{ }mo{{l}^{-1}}\] for the catalysed reaction. How many times the rate of this catalysed reaction greater than that of uncatalysed reaction? \[(Given\,\,{{e}^{3.33}}=28)\]

    A) 15 times           

    B) 38 times

    C)  22 times                      

    D) 28 times

    Correct Answer: D

    Solution :

    [D]
    \[A\to B\,\,(uncatalsed\,\,reaction)\]
    \[A\xrightarrow{catalyst}B\,\,(catalyst\,\,reaction)\]
    \[K=A{{e}^{-{{E}_{a}}/RT}}\]
    \[{{K}_{cat.}}=A{{e}^{-{{E}_{a(cat.)}}/RT}}\]
    \[\frac{{{K}_{cat}}}{K}={{e}^{({{E}_{a}}-E{{'}_{a}})}}\times \frac{1}{RT}\]
    \[\frac{{{K}_{cat}}}{K}={{e}^{\frac{8.314\times {{10}^{3}}}{8.314\times 300}}}={{e}^{3.33}}=28\,\,times\]


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