KVPY Sample Paper KVPY Stream-SX Model Paper-3

  • question_answer
    Let \[{{a}_{1}},\]\[{{a}_{2,}}\]...\[{{a}_{30}}\] be an A.P., \[S=\sum\limits_{i=1}^{30}{ai}\] and \[\sum\limits_{i=1}^{15}{{{a}_{{{(2i-1)}^{.}}}}}\] If \[{{a}_{5}}=27\] and \[\text{S}-2T=75,\] then \[{{a}_{10}}\] is equal to:

    A) 57                                

    B) 47

    C) 42                                

    D) 52

    Correct Answer: D

    Solution :

    \[{{a}_{1}},\]\[{{a}_{2}},\] ?. \[{{a}_{30}},\] A.P., let d be common difference ?d?
    \[\text{S}=\sum\limits_{i=l}^{30}{{{a}_{i}}},\] \[\text{T}=\sum\limits_{i=l}^{18}{{{a}_{2i-\,1}}}\]
    \[{{a}_{5}}=27\]
    \[\Rightarrow \]   \[{{a}_{1}}+4d=27\]
    \[\Rightarrow \]   \[\text{S}\,-\,2\text{T}=75\]
    \[({{a}_{2}}-{{a}_{1}})+({{a}_{4}}-{{a}_{3}})\,+...+({{a}_{30}}-{{a}_{29}})=75\]
                \[15d=75\]
                \[d=5\]
    by (1),   \[{{a}_{1}}=5\]
    \[\therefore \] \[{{a}_{10}}={{a}_{1}}+9d=7+45=52.\]


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