question_answer

In the circuit diagram shown, \[{{X}_{C}}=100\,\Omega ,\]\[{{X}_{L}}=200\,\Omega \] & \[R=100\,\Omega .\] The effective current through the source is:

A) 2 A                              

B) \[2\sqrt{2}\,A\]

C) \[0.5\,A\]                      

D) \[\sqrt{0.4}\,A\]

Correct Answer: B

Solution :

\[{{I}_{R}}=\frac{V}{R}=\frac{200}{100}=2A\]

\[I'=\frac{V}{{{X}_{L}}-{{X}_{C}}}=\frac{200}{100}=2A\]

\[I=\sqrt{{{I}_{R}}^{2}+I{{'}^{2}}}=2\sqrt{2}\,\,Amp.\]