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KVPY Sample Paper KVPY Stream-SX Model Paper-3

  • question_answer
    The specific conductance of a 0.1 N KCl solution at \[23{}^\circ C\] is \[0.0112\text{ }oh{{m}^{-1}}\text{ }c{{m}^{-1}}.\] The resistance of the cell containing the solution at the same temperature was found to be 55 ohm. The cell constant will be:

    A) \[0.142\text{ }c{{m}^{-1}}\]                

    B) \[0.918\text{ }c{{m}^{-1}}\]

    C) \[1.12\text{ }c{{m}^{-1}}\]                 

    D) \[0.616\text{ }c{{m}^{-1}}\]

    Correct Answer: D

    Solution :

    [D] \[\left[ K=\frac{1}{R}\times \frac{\ell }{a} \right]\] \[0.0112=\frac{1}{55}\times \frac{\ell }{a}\] Cell constant \[\frac{\ell }{a}=0.0112.\,\,\times \,\,55=0.616\]


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