A) 2
B) \[-\,2\]
C) 0
D) 1
Correct Answer: B
Solution :
[B]\[x-y=2\] |
\[x+y+xy\] is to be minimized. |
Putting \[y=x-2.\] |
We get, \[f(x)=2x-2+x\,\,(x-2)\] |
\[f'(x)=2+2x-2=0\] at \[x=0\] |
\[f''(x)=2\Rightarrow x=0\] is a point of minima |
Thus minimum value is at \[x=0\]&\[y=-2.\] |
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