A) \[NaB{{H}_{4}}\]
B) \[LiAl{{H}_{4}}\]
C) \[CuO\cdot CuC{{N}_{2}}{{O}_{4}}\]
D) None of these
Correct Answer: A
Solution :
[a] \[NaB{{H}_{4}}\]is a selective reducing agent, it only reduces aldehyde and ketone group. Groups like ester, cyanide remains unaffected.You need to login to perform this action.
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