A) 756
B) 1512
C) 3024
D) None of these
Correct Answer: B
Solution :
[b] We have, 9 married couples. We can select two men out of 9 in \[{}^{9}{{C}_{2}}\] ways. Since no husband and wife are to play in the same game, two women out of the remaining 7 can be chosen in \[{}^{7}{{C}_{2}}\]ways. If \[{{M}_{1}},\]\[{{M}_{2}},\]\[{{W}_{1}}\]\[{{W}_{2}}\] are chosen, then a team consist of \[{{M}_{1}}{{W}_{1}}\] and \[{{M}_{2}}{{W}_{2}}.\] Thus, the number of ways of arrangement is \[{}^{9}{{C}_{2}}\times {}^{7}{{C}_{2}}\times 2=1512.\]
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