A) 2
B) 1
C) 1.5
D) 3
Correct Answer: A
Solution :
\[{{F}_{e}}{{C}_{2}}{{O}_{4}}\to F{{e}^{+3}}+C{{O}_{2}}\] |
\[F{{e}_{2}}{{({{C}_{2}}{{O}_{4}})}_{3}}\to C{{O}_{2}}\] |
\[F{{e}_{2}}{{(S{{O}_{4}})}_{3}}\to \,No\,oxidation\] |
\[FeS{{O}_{4}}\to F{{e}^{+3}}\] |
\[{{g}_{m}}E\,(KMn{{O}_{4}})={{g}_{m}}E\,(Fe{{C}_{2}}{{O}_{4}})+{{g}_{m}}E\,\,[F{{e}_{2}}{{({{C}_{2}}{{O}_{4}})}_{3}}]+{{g}_{m}}E\,(FeS{{O}_{4}})\] |
\[moles\,\times \,V.F=moles\times V.F.+moles\times V.F.+moles\times V.F.\] |
\[x\times 5=(1\times 3)+(1\times 6)+(1\times 1)\] |
\[5x=10\,(MnO_{4}^{-}\to M{{n}^{+2}})\] |
\[x=2.\] |
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