• # question_answer                         Adorption of a gas follows Freundlich adsorption isotherm. $x$ is the mass of the gas adsorbed on mass m of the adsorbent. The plot of $\log \frac{x}{m}$ versus log p is in the given graph. $\frac{x}{m}$ is proportional to: A) ${{p}^{3/2}}$                                    B) ${{p}^{2/3}}$ C)        ${{p}^{3}}$                           D) ${{p}^{2}}$

$\frac{x}{m}=K{{P}^{\text{1/n}}}$ $\log \frac{x}{m}=\frac{1}{n}\log \rho +\log K$ Slope $=\tan \theta =\frac{2}{3}=\frac{1}{n}$             $\frac{x}{m}\propto {{p}^{2/3}}.$