question_answer

                        Adorption of a gas follows Freundlich adsorption isotherm. \[x\] is the mass of the gas adsorbed on mass m of the adsorbent. The plot of \[\log \frac{x}{m}\] versus log p is in the given graph. \[\frac{x}{m}\] is proportional to:

A) \[{{p}^{3/2}}\]                                   

B) \[{{p}^{2/3}}\]

C)        \[{{p}^{3}}\]                          

D) \[{{p}^{2}}\]

Correct Answer: B

Solution :

\[\frac{x}{m}=K{{P}^{\text{1/n}}}\] \[\log \frac{x}{m}=\frac{1}{n}\log \rho +\log K\] Slope \[=\tan \theta =\frac{2}{3}=\frac{1}{n}\]             \[\frac{x}{m}\propto {{p}^{2/3}}.\]