| [A] | \[(mol\,{{L}^{-\,1}})\] | [B] | \[(mol\,{{L}^{-\,1}})\] | Initial Rate | \[(mol\,L{{\,}^{-\,1}}s{{\,}^{-1}})\] |
| 0.05 | 0.05 | 0.045 | |||
| 0.10 | 0.05 | 0.090 | |||
| 0.20 | 0.10 | 0.75 |
A) Rate = \[k[A][B]\]
B) Rate = \[k[A]{{[B]}^{2}}\]
C) Rate = \[k{{[A]}^{2}}{{[B]}^{2}}\]
D) Rate =\[k{{[A]}^{2}}[B]\]
Correct Answer: B
Solution :
| \[r=k{{[A]}^{\rho }}{{[B]}^{q}}\] |
| \[\frac{{{r}^{2}}}{{{r}_{1}}}={{\left[ \frac{{{A}_{2}}}{{{A}_{1}}} \right]}^{\rho }}{{\left[ \frac{{{B}_{_{2}}}}{{{B}_{1}}} \right]}^{q}}\] |
| \[{{2}^{I}}={{2}^{\rho }}\] \[(p=1)\] |
| \[\frac{{{r}^{3}}}{{{r}_{2}}}={{\left[ \frac{{{A}_{3}}}{{{A}_{2}}} \right]}^{I}}{{\left[ \frac{{{B}_{3}}}{{{B}_{2}}} \right]}^{q}}\] |
| \[\frac{0.720}{0.090}=2{{(2)}^{q}}\] |
| \[\frac{720}{90\times 2}={{2}^{q}}=4={{2}^{2}}\] |
| \[q=2\] |
| \[r=k{{(A)}^{I}}{{[B]}^{2}}.\] |
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