A) less than \[{{q}^{2}}\,(7p-12)\]
B) greater than \[{{q}^{2}}\,(7p-12)\]
C) less than \[{{q}^{2}}\,(12p-7)\]
D) greater than \[{{q}^{2}}\,(12p-7)\]
Correct Answer: A
Solution :
\[3<p<4\] |
\[\Rightarrow \]\[{{p}^{2}}-7p+12<0\] and \[q>4\]or \[q<3\] |
\[\Rightarrow \]\[{{q}^{2}}-7q+12>0\] |
\[\therefore \]\[{{p}^{2}}\,(7q-12)<{{q}^{2}}(7p-12)\] |
You need to login to perform this action.
You will be redirected in
3 sec