A) \[-164\]
B) 164
C) \[-160\]
D) 160
Correct Answer: C
Solution :
\[x=-\,5+4i\] \[\Rightarrow \] \[{{(x+5)}^{2}}=-16\] |
\[\Rightarrow \] \[{{x}^{2}}+10x+41=0\] |
\[{{x}^{4}}+9{{x}^{3}}+35{{x}^{2}}-x+4=({{x}^{2}}+10x+41)\] |
\[({{x}^{2}}-x+4)-160\] |
Since \[{{x}^{2}}+10x+41=0\] |
\[\therefore \] \[{{x}^{4}}+9{{x}^{3}}+35{{x}^{2}}-x+4=-160\] |
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