KVPY Sample Paper KVPY Stream-SX Model Paper-6

  • question_answer
    In the figure, given that \[{{V}_{BB}}\] supply can vary from 0 to 5.0 V, \[{{V}_{cc}}=5V,\]\[{{\beta }_{dc}}=200,\] \[{{R}_{B}}=100K\Omega ,\] \[{{R}_{C}}=1k\Omega \] an \[{{V}_{BE}}=1.0V,\] The minimum base current and input voltage at which the transistor will go to saturation, will be respectively:

    A) \[25\mu \,A\,and\,3.5\,V\]           

    B) \[20\mu \,A\,and\,3.5\,V\,\]

    C) \[25\mu A\,and\,2.8\,V\]

    D) \[20\mu A\,and\,2.8\,V\]

    Correct Answer: A

    Solution :

    When switched on:
    \[{{V}_{CE}}=0\]
    \[{{V}_{CC}}-{{R}_{C}}{{I}_{C}}=0\]
    \[{{i}_{C}}=\frac{{{V}_{CC}}}{{{R}_{C}}}=5\times {{10}^{-3}}A\]
    \[{{i}_{C}}=B{{i}_{B}}\]
    \[\Rightarrow \]   \[{{i}_{B}}=25\mu A\]
    \[\Rightarrow \]   \[{{V}_{BB}}={{i}_{B}}{{R}_{B}}-{{V}_{BE}}=0\]
    \[\Rightarrow \]   \[{{V}_{BB}}={{V}_{BE}}+{{i}_{B}}{{R}_{B}}=3.5V.\]


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