A) \[1.5\times {{10}^{-3}}\,V\]
B) \[1.1\times {{10}^{-3\,}}\,V\]
C) \[2.5\times {{10}^{-3}}\,V\]
D) \[0.3\times {{10}^{-3}}\,V\]
Correct Answer: B
Solution :
\[\therefore \] \[Emf=B\ell \nu \sin \,45{}^\circ \] \[=(0.3\times {{10}^{-4}})\times 10\times 5\times \frac{1}{\sqrt{2}}\] \[=1.1\times {{10}^{-3}}V.\]You need to login to perform this action.
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