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KVPY Sample Paper KVPY Stream-SX Model Paper-6

  • question_answer
    A sample of 16 g charcoal was brought into contact with \[C{{H}_{4}}\] gas contained in a vessel of litre at \[27 {}^\circ C\]. The pressure of gas was found to fall from \[760\] to 608 torr. The density of charcoal sample is \[1.6\text{ }g/c{{m}^{3}}\]. What is the volume of the \[{{\operatorname{CH}}_{4}}\]Gas adsorbed per gram of the adsorbent at 608 torr and\[27 {}^\circ C\]?

    A) \[125mL/g\]                   

    B) \[16.25mL/g\]

    C) \[25mL/g\]                    

    D) None of these

    Correct Answer: B

    Solution :

    Final volume of gas, at 608 torr pressure  \[{{\operatorname{V}}_{2}}=\frac{{{P}_{1}}{{V}_{1}}}{{{P}_{2}}};=\frac{760\times 1}{608}\]\[\Rightarrow \]\[1.25L\] or \[{{V}_{2}}=1250mL\]
    Volume occupied by gas =volume of vessel -volume occupied by charcoal \[=1000-\frac{16}{1.6}=990\operatorname{mL}\]
    Difference of volume is due to adsorption of gas by charcoal
    \[\therefore \]Volume of gas adsorbed by charcoal \[=1250-990\]\[\Rightarrow \]\[260\operatorname{mL}\]
    Volume of the gas adsorbed per gram of charcoal
    \[=\frac{260}{16}=16.25\operatorname{mL}/g\,\]at 608 torr and \[27{}^\circ \operatorname{C}.\]


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