A) \[\underset{\scriptscriptstyle-}{N}{{O}_{2}}\,and\ {{\underset{\scriptscriptstyle-}{N}}_{2}}{{O}_{4}}\]
B) \[{{\underset{\scriptscriptstyle-}{P}}_{2}}{{O}_{5\,}}\operatorname{and}\,{{\underset{\scriptscriptstyle-}{P}}_{4}}{{\operatorname{O}}_{10}}\]
C) \[{{\underset{\scriptscriptstyle-}{N}}_{2}}O\,and\ \underset{\scriptscriptstyle-}{N}O\]
D) \[\underset{\scriptscriptstyle-}{S}{{O}_{2}} and \underset{\scriptscriptstyle-}{S}{{O}_{3}}\]
Correct Answer: D
Solution :
| O.N. of N in \[N{{O}_{2}}\] and \[{{N}_{2}}{{O}_{4}}\] is +4 |
| \[\therefore \]Difference is zero. |
| O.N. of P in \[{{P}_{2}}{{O}_{5}}\] and \[{{P}_{4}}{{O}_{10}}\] is +5 |
| \[\therefore \]Difference is zero |
| O.N. of N in\[{{\operatorname{N}}_{2}}O\]is +1and in NO is +2.the difference is 1 |
| O.N. of \[\operatorname{S}\] in \[{{\operatorname{SO}}_{2}}\]is +4 and in \[{{\operatorname{SO}}_{3}}\] is +6. The difference is +2 |
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