| \[{{S}_{1}}\]: Potential energy of the two opposite charge system increases with the decrease in distance. |
| \[{{S}_{2}}\]: When an electron make transition from higher orbit to lower orbit it's kinetic energy increases. |
| \[{{S}_{3}}\]: When an electron make transition from lower energy to higher energy state its potential energy increases. |
| \[{{S}_{4}}\]: 11eV photon can free an electron from the 1st excited state of \[H{{e}^{+}}\]- ion. |
A) TTTT
B) FTTF
C) TFFT
D) FFFF
Correct Answer: B
Solution :
| \[{{S}_{1}}:\]Potential energy of the two opposite charge system decreases with decreases in distance, |
| \[{{S}_{4}}:\] the energy of lst excited state of \[H{{e}^{+}}\]ion |
| \[=-3.4\,{{Z}^{2}}=-3.4\times {{2}^{2}}\] \[-13.6\,eV.\] |
| \[{{S}_{2}}\] and \[{{S}_{3}}\] are correct statement. |
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