A) \[CuS{{O}_{4}},S{{O}_{2}},C{{u}_{2}}O\]
B) \[N{{a}_{2}}{{C}_{2}}{{O}_{4}},CO,C{{O}_{2}}\]
C) \[PbC{{O}_{3}},C{{O}_{2}},PbS{{O}_{4}}\]
D) \[CaC{{O}_{3}},C{{O}_{2}},CaS{{O}_{4}}\]
Correct Answer: C
Solution :
\[PbC{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}PbS{{O}_{4}}+C{{O}_{2}}+{{H}_{2}}O\] \[PbS{{O}_{4}}\]forms a film around \[PbC{{O}_{3}}\]. Thus slowly reaction ceases
You need to login to perform this action.
You will be redirected in
3 sec
