| The diagram shows the inheritance of hemophilia in a family. |
 |
| If daughter 4 marries a normal male, what is the probability that their first child would suffer from hemophilia? |
A) 0
B) 0.125
C) 0.25
D) 0.5
Correct Answer: B
Solution :
| Daughter 4 : \[X{{X}^{h}},XX\]where \[{{X}^{h}}\]is the gene for hemophilia. |
| Probability of her being a carrier = 0.6 |
| Normal male XY |
 |
| Probability of a haemophilic = 0.26 |
| Therefore, probability of daughter 4 having a haemophilic child \[=0.5\times 0.25=0.125\] |
You need to login to perform this action.
You will be redirected in
3 sec
