A) \[{{H}_{2}}+{{I}_{2}}\to 2HI\]
B) \[{{H}_{2}}+C{{l}_{2}}\to 2HCl\]
C) \[{{H}_{2}}+B{{r}_{2}}\to 2HBr\]
D) \[{{H}_{2}}+{{F}_{2}}\to 2HF\]
Correct Answer: A
Solution :
First reaction will be requiring a catalyst among halogens oxidizing power decrease down the group.
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