A) \[\left( \frac{2}{3},\frac{1}{3} \right)\]
B) \[\left( \frac{7}{6},\frac{1}{6} \right)\]
C) \[\left( \frac{13}{6},\frac{11}{6} \right)\]
D) \[\left( \frac{1}{6},\frac{5}{6} \right)\]
Correct Answer: C
Solution :
\[\cos \pi \,\,(x+y)\cos \pi \,\,(x-y)=\frac{1}{2}\] |
\[\cos \pi \,\,(x+y)=1\] |
\[\pi \,\,(x+y)=2n\pi \] |
\[x+y=2n\] |
\[x-y=\frac{1}{3}\] |
Hence, \[x=n+\frac{1}{6}\] |
\[y=n-\frac{1}{6}\] |
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