A) \[f(x)>f(y)>f(z)\]
B) \[f(x)<f(y)<f(z)\]
C) \[f(y)<f(x)<f(z)\]
D) \[f(y)<f(z)<f(x)\]
Correct Answer: C
Solution :
let \[f(x)\ne 2\]be true and \[f(y)=2,\]\[f(z)\ne 1\]are false |
\[\Rightarrow f(x)\ne 2,f(y)\ne 2,f(z)=1\] |
\[\Rightarrow f(x)=3,f(y)=3,f(z)=1\] |
But then function is many one, similarly two other cases. |
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