A uniform rod of length L is charged uniformly with charge q and is rotating about an axis passing through its centre and perpendicular to rod. Magnetic moment of the rod is: |
A) \[\frac{q{{L}^{2}}\omega }{6}\]
B) \[\frac{q{{L}^{2}}\omega }{12}\]
C) \[\frac{q{{L}^{2}}\omega }{24}\]
D) \[\frac{q{{L}^{2}}\omega }{36}\]
Correct Answer: C
Solution :
\[\frac{M}{L}=\frac{q}{2m}\] \[M=\frac{q}{2m}\cdot L\] \[M=\frac{q}{2m}\cdot \frac{m{{L}^{2}}}{12}\cdot \omega \] \[M=\frac{q{{L}^{2}}\omega }{24}\]You need to login to perform this action.
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