A) \[S,\text{ }{{S}_{3}}{{N}_{2}},\text{ }S{{O}_{2}}\]
B) \[C,\text{ }{{C}_{2}}{{N}_{2}},\text{ }N{{H}_{3}}\]
C) \[Fe,\text{ }FeO,\text{ }Fe{{\left( OH \right)}_{2}}\]
D) \[Ca,\text{ }C{{a}_{3}}{{N}_{2}},\text{ }Ca{{\left( OH \right)}_{2}}\]
Correct Answer: D
Solution :
| \[\underset{Metal\,\,(A)}{\mathop{3Ca}}\,+{{N}_{2}}\to \underset{(B)calcium\,\,nitrate}{\mathop{C{{a}_{3}}{{N}_{2}}}}\,\] |
| (The case of formation of nitrides decreases from Be \[\to \] Ba) |
| \[\underset{(B)}{\mathop{C{{a}_{3}}{{N}_{2}}}}\,+6{{H}_{2}}O\to \underset{(C)}{\mathop{3\,Ca\,\,{{(OH)}_{2}}}}\,+\underset{(D)}{\mathop{2\,N{{H}_{3}}}}\,\] |
| cal. hydroxide |
| \[Ca\,\,{{(OH)}_{2}}+\underset{Milkiness}{\mathop{C{{O}_{2}}\to CaC{{O}_{3}}}}\,\downarrow +{{H}_{2}}O\] |
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