A) \[\frac{1}{x+y}={{x}^{2}}+c{{e}^{x}}+1\]
B) \[\frac{1}{{{(x+y)}^{2}}}={{x}^{2}}+c{{e}^{{{x}^{2}}}}+1\]
C) \[\frac{1}{{{(x+y)}^{2}}}=x+c{{e}^{x}}+1\]
D) \[\frac{1}{x+y}=x+c{{e}^{{{x}^{2}}}}+1\]
Correct Answer: B
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