then x is equal to:
A) 2
B) 7
C) \[-9\]
D) All of these
Correct Answer: D
Solution :
[d]
Applying \[{{R}_{1}}\to {{R}_{1}}+{{R}_{2}}+{{R}_{3}}\] 
\[\Rightarrow (x+9)(x-2)(x-7)=0\] \[~\Rightarrow x=2,7,-9\] Hence option [d] is correct.
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