A) \[\frac{\pi }{4}\]
B) p
C) \[\frac{\pi }{2}\]
D) \[\frac{3\pi }{4}\]
Correct Answer: A
Solution :
[a] \[\because z=1+i\] Here, \[x=1,y=1\] \[\therefore \tan \theta =\left( \frac{y}{x} \right)=\frac{1}{1}=1=\tan \frac{\pi }{4}\] \[\theta =\frac{\pi }{4}\] \[\because P\equiv \left( 1,1 \right)\]lies in 1st quadrant. \[\therefore \]The principal value of the amplitude\[z=\frac{\pi }{4}\]You need to login to perform this action.
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