question_answer

Solution of \[\frac{dy}{dx}+x(x+y)+1={{x}^{3}}{{(x+y)}^{3}}\]is

A)  \[\frac{1}{x+y}={{x}^{2}}+c{{e}^{x}}+1\]

B)  \[\frac{1}{{{(x+y)}^{2}}}={{x}^{2}}+c{{e}^{{{x}^{2}}}}+1\]

C)  \[\frac{1}{{{(x+y)}^{2}}}=x+c{{e}^{x}}+1\]

D)  \[\frac{1}{x+y}=x+c{{e}^{{{x}^{2}}}}+1\]