question_answer

In given figure \[\Delta \]ABC is an isosceles triangle with AB = AC.

Take a trace-copy of \[\Delta \]ABC and also name it as \[\Delta \]ACB.

(a) State the three pairs of equal parts in \[\Delta \]ABC and \[\Delta \]ACB.

(b) Is\[\Delta ABC\cong \Delta ACB\]? Why or why not?

(c) Is \[\angle \]B = \[\angle \]C?

Answer:

(a) In the given triangles DABC and DACB,

AB = AC

AC = AB

\[\angle A=\angle A\]

(b) As all the three corresponding sides of \[\Delta ABC\]and \[\Delta ACB\]are equal.

Hence, by S.S.S. congruency

\[\Delta ABC\cong \Delta ACB\]

(c) By c.p.c.t., \[\angle B=\angle C\].