8th Class Mathematics Sample Paper Mathematics Sample Paper - 10

  • question_answer
    Simplify : \[\frac{16}{39}+\frac{9}{-26}\]

    Answer:

    We have         \[\frac{16}{39}+\frac{9}{(-26)}=\frac{16}{39}+\frac{-9}{26}\]
    Now, the LCM of 39 and 26 is 78.
    \[\therefore \] Rewritine \[\frac{16}{39}\] and \[\frac{-9}{26}\] in such a manner they have the same denominator 78.
    \[\frac{16}{39}=\frac{16\times 2}{39\times 2}=\frac{32}{78}\]
    \[\frac{-9}{26}=\frac{-9\times 3}{26\times 3}=\frac{-27}{78}\]
    \[\frac{16}{39}+\frac{-9}{26}=\frac{32}{78}+\frac{(-27)}{78}\]
    \[=\frac{32+(-27)}{78}\]
    \[=\frac{32-27}{78}=\frac{5}{78}\]      
         


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