question_answer

ABCD is a parallelogram in which AB = 8 cm, AD = 6 cm and AE = 4 cm. Find the altitude corresponding to side AD.

Answer:

Area of parallelogram \[ABCD\text{ }=\text{ }AB\text{ }\times \text{ }AE\] \[=8\times 4\text{ }c{{m}^{2}}=32\text{ }c{{m}^{2}}\] Let altitude corresponding to AD be h. Then, \[h\times AD=32\] or          \[h\times 6=32\] or         \[h=\frac{32}{6}=\frac{16}{3}\] Thus, altitude corresponding to AD is ? csjl 3