Answer:
Steps of Construction : (a) Draw a line segment AC = 6·6 cm. (b) Draw perpendicular bisector XY of AC, which meets AC at M. (c) With centre M take the radius =\[=\frac{1}{2}\times 5.6\]cm i.e., 2·8 cm, draw arcs to intersect XY at B and D. (d) Joint AB, BC, CD and AD. Thus, ABCD is the required rhombus.
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