Answer:
It is clear that the least number divisible by 6, 15 and 18 is their LCM. Therefore, the required number must by 5 more than their LCM. Now the LCM of 6, 15, 18
LCM \[=3\times 2\times 3\times 5=90\] Thus, the required number = 90 + 5 = 95 2 6, 15, 18 3 3, 15, 9 3 1, 5, 3 5 1, 5, 1 1 1, 1, 1
You need to login to perform this action.
You will be redirected in
3 sec