question_answer

Draw a triangle ABC with BC = 3.2 cm, AB = 3.6 cm and \[\angle \]B =\[120{}^\circ \]. Also draw a perpendicular from A on BC.

Answer:

We follow the following steps to construct the required triangle :

Steps of Construction:

(a) Draw ZXBY of measure 120°.

(b) From ray BX, cut off line segment BC of length 3.2 cm.

(c) From ray BY, cut off line segment BA of length 3.6 cm.

(d) Join CA to obtain the required triangle.

(e) Draw ray BZ.

(f) With centre A, draw an arc intersecting rays

BX and BZ at P and Q respectively.

(g) With centre P and radius more than - (PQ), cut an arc on the opposite of A.

(h) With centre Q and the same radius as in step VII, cut on arc which intersect the arc drawn in step VII at R,

(i) Join AR. If it meets BZ at L, then AL is the required perpendicular from A on BC.