question_answer

ABC is a right angled triangle whose sides are AB = 8 cm, BC = 12 cm and AC = 13 cm. Find the area Of \[\Delta ABC\] and height \[BD\bot AC.\].

Answer:

Area of the triangle ABC \[=\frac{1}{2}\times base\,\,\times \,\,Height\] \[=\frac{1}{2}\times AB\,\times \,\,BC\] \[=\frac{1}{2}\times 8\,\times \,\,12\] = 4 × 12 \[=48\,{{m}^{2}}\]                                                                                                      Again, also area of ΔABC \[=\frac{1}{2}\times AC\times BD\] \[48=\frac{1}{2}\times 13\times BD\] D = 96 Thus, BD =\[\frac{96}{13}\]= 7.38 cm