(a) \[{{(b-7)}^{2}}\] |
(b) \[{{(xy+3z)}^{2}}\] |
(c) \[{{(6{{x}^{2}}-5y)}^{2}}\] |
(d) \[{{\left( \frac{2}{3}m+\frac{3}{2}n \right)}^{2}}\] |
(e) \[{{(0.4p-0.5q)}^{2}}\] |
(f) \[{{(2xy+5y)}^{2}}\] |
Answer:
(a) \[{{(b7)}^{2}}\] Use the identity, \[{{(ab)}^{2}}={{a}^{2}}2ab+{{b}^{2}}\] \[={{b}^{2}}2(b)(7)+{{\left( 7 \right)}^{2}}\] \[={{b}^{2}}14b+\text{ }49\] (b) \[{{(xy+3z)}^{\mathbf{2}}}\] Use the identity, \[{{(a+b)}^{2}}={{a}^{2}}+2ab+{{b}^{2}}={{(xy)}^{2}}+2(xy)(3z)+{{(3z)}^{2}}\] \[={{x}^{2}}{{y}^{2}}+6xyz+9{{z}^{2}}\] (c) \[{{(6{{x}^{2}}5y)}^{2}}={{(6x)}^{2}}2(6x)(5y)+{{(5y)}^{2}}\] Use the identity, \[{{(ab)}^{2}}={{a}^{2}}2ab+{{b}^{2}}\] \[=36{{x}^{4}}12x\times 5y+25{{y}^{2}}\] \[=\text{ }36{{x}^{4}}60{{x}^{2}}y+25{{y}^{2}}\] (d) \[{{\left( \frac{2}{3}m+\frac{3}{2}n \right)}^{2}}\] Use the identity, \[{{(a+b)}^{2}}={{a}^{2}}+2ab+{{b}^{2}}\] \[={{\left( \frac{2}{3}m \right)}^{2}}+2\left( \frac{2}{3}m \right)\left( \frac{3}{2}n \right)+{{\left( \frac{3}{2}n \right)}^{2}}\] \[=\frac{4}{9}{{m}^{2}}+\frac{4}{3}m\left( \frac{3}{2}n \right)+{{\left( \frac{9}{4}n \right)}^{2}}\] \[=\frac{4}{9}{{m}^{2}}+2mn+\frac{9}{4}{{n}^{2}}\] (e) \[{{(0.4p0.5q)}^{2}}\] Use the identity, \[{{(ab)}^{2}}={{a}^{2}}2ab+{{b}^{2}}\] \[={{(0.4p)}^{2}}2\text{ }\left( 0.4 \right)\left( 0.5 \right)\text{ }(p\times q)+{{(0.5q)}^{2}}\] \[=0.16{{p}^{2}}\text{ }\left( 0.8 \right)\left( 0.5 \right)pq+0.25{{q}^{2}}\] \[=0.16{{p}^{2}}0.40pq+0.25{{q}^{2}}\] (f) \[{{(2xy+5y)}^{2}}\] Use the identity, \[{{(a+b)}^{2}}={{a}^{2}}+2ab+{{b}^{2}}\] \[={{(2xy)}^{2}}+\text{ }2(2xy)\text{ }(5y)+{{(5y)}^{2}}\] \[=\text{ }4{{x}^{2}}{{y}^{2}}+4xy\times 5y+25{{y}^{2}}\] \[=\text{ }4{{x}^{2}}{{y}^{2}}+\text{ }20x{{y}^{2}}+25{{y}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec