Answer:
Area of a tile \[=\text{ }25\times 20\,c{{m}^{2}}=500\,\,c{{m}^{2}}\] ∴ Area of 2400 tiles \[=\text{ }2400\times 500\text{ }c{{m}^{2}}\] \[=\text{ }1200000\text{ }c{{m}^{2}}\] \[=\frac{1200000}{10000}{{m}^{2}}\] \[\left[ \therefore \text{ }10000\text{ }c{{m}^{2}}=\text{ }1\text{ }{{m}^{2}} \right]\]\[=\text{ }120\text{ }{{m}^{2}}\] Let the height of the wall be h metres then, Area of the wall \[=\text{ }4h\text{ }{{m}^{2}}\] Since 2400 tiles completely cover the wall. ∴ Area of the wall = Area of 2400 tiles 4h = 120 \[\frac{4h}{4}=\frac{120}{4}\] h = 30 [Dividing both sides by 4] Hence, the height of the wall is 30 metre.
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