• # question_answer If the division $N\div 5$ leaves a remainder of 4, what might be the one's digit of N? Suppose that the division $N\div 5$ leaves a remainder of 4 and the division $N\div 2$ leaves a remainder of 1. What must be the one's digit of N

 If remainder = 4, then the one?s digit of ?N? must be either 4 or 9. For $N\div 5,$ remainder = 4 One?s digit can be 4 or 9.                   ...(i) Again, for N ÷ 2, remainder = 1 N must be an odd number. So, one?s digit of N must be 1, 3, 5, 7 or 9. ...(ii) From (i) and (ii), the one?s digit of N must be 9.