Answer:
Let the sides of two squares are a and b respectively. 4a = 40 and 4b = 96 \[\therefore \] a = 10 m and b = 24 m Given, The perimeter of another square = Sum of area of two squares. = Area of Ist square + Area of IInd square \[={{a}^{2}}+{{b}^{2}}\] \[={{\left( 10 \right)}^{2}}+{{\left( 24 \right)}^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\] =100 + 576 = 676 m2 Hence, the perimeter of another square = 676 m.
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