Answer:
Let ABC be an equilateral triangle. Since, all the angles of an equilateral triangle are equal. \[\therefore \]\[\angle A\text{ }=\text{ }\angle B\text{ }=\text{ }\angle C\text{ }=\text{ }x{}^\circ \] (say) We know that, sum of all the angles of a triangle is 180°. \[\angle A\text{ }+\text{ }\angle B\text{ }+\text{ }\angle C\text{ }=\text{ }180{}^\circ \] \[x{}^\circ \text{ }+\text{ }x{}^\circ \text{ }+\text{ }x{}^\circ \text{ }=\text{ }180{}^\circ \] \[3x{}^\circ \text{ }=\text{ }180{}^\circ \] \[x{}^\circ \text{ }=\text{ }60{}^\circ \] Hence, \[\angle A\text{ }=\text{ }\angle B\text{ }=\text{ }\angle C\text{ }=\text{ 60}{}^\circ \]
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