Answer:
Steps of Construction: (a) Draw a line segment PQ = 5 cm. (b) At P, construct\[\angle QPX=45{}^\circ \]. (c) At Q construct\[\angle PQY=75{}^\circ \]. (d) Let the rays \[\overline{PX}\]and \[\overline{QY}\]intersect at R. Thus \[\Delta PQR\]is the required triangle.
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